6^-x+3*6^2x=6^-x

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Solution for 6^-x+3*6^2x=6^-x equation:



6^-x+3*6^2x=6^-x
We move all terms to the left:
6^-x+3*6^2x-(6^-x)=0
We add all the numbers together, and all the variables
-1x+3*6^2x-(6^-x)=0
Wy multiply elements
18x^2-1x-(6^-x)=0
We get rid of parentheses
18x^2-1x+x-6^=0
We add all the numbers together, and all the variables
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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